Algebra 2

Why Do Parabolas Look Like That?

Every quadratic function produces a parabola — that familiar U-shape. But why does changing a single number reshape the entire curve? Let’s find out by breaking one apart.

Start Simple

Here’s the simplest quadratic: y = x²

-5-4-3-2-112345-2-112345678910(0, 0)

Every x gets squared — negative inputs become positive, so the curve is symmetric. The vertex sits at the origin (0, 0).

What Does Each Number Do?

The general form is y = ax² + bx + c. Use the sliders to change each coefficient and watch the parabola respond:

a0
-33
b0
-55
c0
-55
y=0x2+0x+0y = 0x^2 + 0x + 0
-8-6-4-22468-10-8-6-4-2246810(-8, 0)
Try This

Experiment with these:

  • Set a to a negative number — what happens to the U shape?
  • Make a close to zero — the parabola gets wider. Why?
  • Leave a = 1, c = 0 and slide b around — watch where the vertex moves!
  • Set a = 0 — what kind of graph do you get?

The Three Coefficients, Decoded

a — The Stretch Factor

b — The Tilt

This one is tricky. It moves the vertex both horizontally and vertically along a hidden path. The vertex x-coordinate is always at x = -b / 2a.

c — The Vertical Shift

The simplest one: c just moves the whole parabola up or down. It’s the y-intercept — the point where the curve crosses the y-axis.

Finding Roots: Where Does the Parabola Cross Zero?

The roots (or zeros) are the x-values where y = 0 — visually, where the parabola crosses the x-axis.

c0
-44
y=x2+0y = x^2 + 0
-4-224-4-22468

Slide c and watch:

Connection

This is exactly what the discriminant (b² - 4ac) tells you. It’s not just a formula to memorize — it answers a geometric question: does this parabola actually touch the x-axis?

  • Discriminant > 0 → two crossings (two roots)
  • Discriminant = 0 → one touch (one repeated root)
  • Discriminant < 0 → no crossing (no real roots)

Comparing Parabolas

Here are three parabolas with different a values, all passing through the origin. Notice how a controls the “width”:

-5-4-3-2-112345-112345678910y = 0.25x²y = x²y = 3x²

The larger |a| is, the steeper the sides. Think of it as how “quickly” the function grows away from the vertex.

Challenge

Challenge: Can you find values of a, b, and c that make the parabola pass through the points (1, 0) and (3, 0) with a vertex at (2, -1)?

Go back to the sliders above and try it! Hint: start with the roots to figure out what the factored form looks like.

Take the Quiz